### Java DecimalFormat - For Large Decimal Point Numbers

The Java DecimalFormat class helps us to format numbers in many ways. I was trying to converta big number to a 2 decimal point number.Thought of sharing the same with some explaination.

Trying to achieve this: 1,308,207 ---> 1.31

```
String number = "1,308,207";
java.text.DecimalFormat df = new java.text.DecimalFormat("#.##");
number = number.replace(",", "");
Float f = Float.parseFloat(number) / 1000000;
String result = df.format(f);
System.out.println(result); // result = 1.31
```

#### So how does it work??

Well it works like this. DecimalFromat uses java.math.RoundingMode.HALF_EVEN method whichrounds off the number to nearest even i.e when it's 0.05 it becomes 0.1.

1. The number becomes 1308207 at line 3.

2. At line no. 5 it becomes 1.308207.

3. Now the actual formatting starts:-

4. The right hand side(RHS) value is 07,so nearest round off is 10, only 1 taken & RHS discarded.

5. Now the number becomes 1.308201

6. Rightmost 01,the nearest round off id 00, RHS discarded & number becomes 0.

7. Again number becomes smaller 1.30820, in same way becomes 1.3082.

8. Next step : 1.308

9. Finally 1.31(08 becomes 10 with HALF_EVEN method and 0 discarded).

Do you have suggestions or want to improve the solution? Please do feel free to write back to us